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Simplifying x[(2x + 1)(x + 1)] = 1 Reorder the terms: x[(1 + 2x)(x + 1)] = 1 Reorder the terms: x[(1 + 2x)(1 + x)] = 1 Multiply (1 + 2x) * (1 + x) x[(1(1 + x) + 2x * (1 + x))] = 1 x[((1 * 1 + x * 1) + 2x * (1 + x))] = 1 x[((1 + 1x) + 2x * (1 + x))] = 1 x[(1 + 1x + (1 * 2x + x * 2x))] = 1 x[(1 + 1x + (2x + 2x2))] = 1 Combine like terms: 1x + 2x = 3x x[(1 + 3x + 2x2)] = 1 [1 * x + 3x * x + 2x2 * x] = 1 [1x + 3x2 + 2x3] = 1 Solving 1x + 3x2 + 2x3 = 1 Solving for variable 'x'. Reorder the terms: -1 + 1x + 3x2 + 2x3 = 1 + -1 Combine like terms: 1 + -1 = 0 -1 + 1x + 3x2 + 2x3 = 0 The solution to this equation could not be determined.
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